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摘要
探讨了玫瑰精B与赖诺普利的相互作用,建立了测定药物中赖诺普利的荧光分析新方法。在λex/λem=556 nm/585 nm、pH 7.50 Tris-盐酸条件下,玫瑰精B与赖诺普利反应生成二元离子缔合物,使体系的荧光强度显著增强,赖诺普利的质量浓度在0.06~4.1 mg/L范围内与体系的荧光增强强度(ΔF)呈线性关系,检出限(3Sb/S)为0.009 2 mg/L。该方法可用于市售赖诺普利片剂和胶囊中赖诺普利的测定,回收率为98.7%~103%,相对标准偏差RSD(n=6)为2.2%~2.8%。
Abstract
The interaction action between rhodamine B and lisinopril is discussed and a novel fluorescence analysis method for determination of lisinopril in drugs is established.Under the conditions of λex/λem=556 nm/585 nm and Tris-hydrochloric acid of pH 7.50,rhodamine B reacts with lisinopril to form a binary ion association complexes,which enhances distinctly the fluorescence intensity of the system.The mass concentration of lisinopril in the range of 0.06 to 4.1 mg·L-1 is directly proportional to fluorescence enhancement intensity (ΔF) of the system,with a detection limit (3Sb/S) of 0.009 2 mg·L-1.This method can be applied to the determination of lisinopril in commercially available lisinopril tablets and capsules,with recovery between 98.7% and 103%,and the relative standard deviations RSD (n=6) in the range of 2.2%-2.8%.
关键词
赖诺普利
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荧光光谱
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玫瑰精B
Key words
lisinopril
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fluorescence spectra
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rhodamine B
Author summay
何树华(1971-),女,理学学士,教授,研究方向为分子光谱分析,heshuhua20182019@163.com
玫瑰精B与赖诺普利相互作用及其荧光光谱分析与应用[J].
现代化工, 2019, 39(2): 235-237 DOI:10.16606/j.cnki.issn0253-4320.2019.02.053